1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
|
/* -*- tab-width: 2; indent-tabs-mode: nil; js-indent-level: 2 -*- */
/* This Source Code Form is subject to the terms of the Mozilla Public
* License, v. 2.0. If a copy of the MPL was not distributed with this
* file, You can obtain one at http://mozilla.org/MPL/2.0/. */
/**
File Name: 15.1.2.5-2.js
ECMA Section: 15.1.2.5 Function properties of the global object
unescape( string )
Description:
This tests the cases where there are fewer than 4 characters following "%u",
or fewer than 2 characters following "%" or "%u".
The unescape function computes a new version of a string value in which
each escape sequences of the sort that might be introduced by the escape
function is replaced with the character that it represents.
When the unescape function is called with one argument string, the
following steps are taken:
1. Call ToString(string).
2. Compute the number of characters in Result(1).
3. Let R be the empty string.
4. Let k be 0.
5. If k equals Result(2), return R.
6. Let c be the character at position k within Result(1).
7. If c is not %, go to step 18.
8. If k is greater than Result(2)-6, go to step 14.
9. If the character at position k+1 within result(1) is not u, go to step
14.
10. If the four characters at positions k+2, k+3, k+4, and k+5 within
Result(1) are not all hexadecimal digits, go to step 14.
11. Let c be the character whose Unicode encoding is the integer represented
by the four hexadecimal digits at positions k+2, k+3, k+4, and k+5
within Result(1).
12. Increase k by 5.
13. Go to step 18.
14. If k is greater than Result(2)-3, go to step 18.
15. If the two characters at positions k+1 and k+2 within Result(1) are not
both hexadecimal digits, go to step 18.
16. Let c be the character whose Unicode encoding is the integer represented
by two zeroes plus the two hexadecimal digits at positions k+1 and k+2
within Result(1).
17. Increase k by 2.
18. Let R be a new string value computed by concatenating the previous value
of R and c.
19. Increase k by 1.
20. Go to step 5.
Author: christine@netscape.com
Date: 28 october 1997
*/
var SECTION = "15.1.2.5-2";
var VERSION = "ECMA_1";
startTest();
var TITLE = "unescape(string)";
writeHeaderToLog( SECTION + " "+ TITLE);
// since there is only one character following "%", no conversion should occur.
for ( var CHARCODE = 0; CHARCODE < 256; CHARCODE += 16 ) {
new TestCase( SECTION,
"unescape( %"+ (ToHexString(CHARCODE)).substring(0,1) +" )",
"%"+(ToHexString(CHARCODE)).substring(0,1),
unescape( "%" + (ToHexString(CHARCODE)).substring(0,1) ) );
}
// since there is only one character following "%u", no conversion should occur.
for ( var CHARCODE = 0; CHARCODE < 256; CHARCODE +=16 ) {
new TestCase( SECTION,
"unescape( %u"+ (ToHexString(CHARCODE)).substring(0,1) +" )",
"%u"+(ToHexString(CHARCODE)).substring(0,1),
unescape( "%u" + (ToHexString(CHARCODE)).substring(0,1) ) );
}
// three char unicode string. no conversion should occur
for ( var CHARCODE = 1024; CHARCODE < 65536; CHARCODE+= 1234 ) {
new TestCase
( SECTION,
"unescape( %u"+ (ToUnicodeString(CHARCODE)).substring(0,3)+ " )",
"%u"+(ToUnicodeString(CHARCODE)).substring(0,3),
unescape( "%u"+(ToUnicodeString(CHARCODE)).substring(0,3) )
);
}
test();
function ToUnicodeString( n ) {
var string = ToHexString(n);
for ( var PAD = (4 - string.length ); PAD > 0; PAD-- ) {
string = "0" + string;
}
return string;
}
function ToHexString( n ) {
var hex = new Array();
for ( var mag = 1; Math.pow(16,mag) <= n ; mag++ ) {
;
}
for ( index = 0, mag -= 1; mag > 0; index++, mag-- ) {
hex[index] = Math.floor( n / Math.pow(16,mag) );
n -= Math.pow(16,mag) * Math.floor( n/Math.pow(16,mag) );
}
hex[hex.length] = n % 16;
var string ="";
for ( var index = 0 ; index < hex.length ; index++ ) {
switch ( hex[index] ) {
case 10:
string += "A";
break;
case 11:
string += "B";
break;
case 12:
string += "C";
break;
case 13:
string += "D";
break;
case 14:
string += "E";
break;
case 15:
string += "F";
break;
default:
string += hex[index];
}
}
if ( string.length == 1 ) {
string = "0" + string;
}
return string;
}
|
