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+/* -*- tab-width: 2; indent-tabs-mode: nil; js-indent-level: 2 -*- */
+/* This Source Code Form is subject to the terms of the Mozilla Public
+ * License, v. 2.0. If a copy of the MPL was not distributed with this
+ * file, You can obtain one at http://mozilla.org/MPL/2.0/. */
+
+
+/**
+ File Name: 15.5.4.7-3.js
+ ECMA Section: 15.5.4.7 String.prototype.lastIndexOf( searchString, pos)
+ Description:
+
+ If the given searchString appears as a substring of the result of
+ converting this object to a string, at one or more positions that are
+ at or to the left of the specified position, then the index of the
+ rightmost such position is returned; otherwise -1 is returned. If position
+ is undefined or not supplied, the length of this string value is assumed,
+ so as to search all of the string.
+
+ When the lastIndexOf method is called with two arguments searchString and
+ position, the following steps are taken:
+
+ 1.Call ToString, giving it the this value as its argument.
+ 2.Call ToString(searchString).
+ 3.Call ToNumber(position). (If position is undefined or not supplied, this step produces the value NaN).
+ 4.If Result(3) is NaN, use +; otherwise, call ToInteger(Result(3)).
+ 5.Compute the number of characters in Result(1).
+ 6.Compute min(max(Result(4), 0), Result(5)).
+ 7.Compute the number of characters in the string that is Result(2).
+ 8.Compute the largest possible integer k not larger than Result(6) such that k+Result(7) is not greater
+ than Result(5), and for all nonnegative integers j less than Result(7), the character at position k+j of
+ Result(1) is the same as the character at position j of Result(2); but if there is no such integer k, then
+ compute the value -1.
+
+ 1.Return Result(8).
+
+ Note that the lastIndexOf function is intentionally generic; it does not require that its this value be a
+ String object. Therefore it can be transferred to other kinds of objects for use as a method.
+
+ Author: christine@netscape.com
+ Date: 2 october 1997
+*/
+var SECTION = "15.5.4.7-3";
+var VERSION = "ECMA_2";
+startTest();
+var TITLE = "String.protoype.lastIndexOf";
+
+writeHeaderToLog( SECTION + " "+ TITLE);
+
+new TestCase( SECTION,
+ "var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 0 )",
+ -1,
+ eval("var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 0 )") );
+
+new TestCase( SECTION,
+ "var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 1 )",
+ 1,
+ eval("var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 1 )") );
+
+new TestCase( SECTION,
+ "var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 2 )",
+ 1,
+ eval("var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 2 )") );
+
+new TestCase( SECTION,
+ "var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 10 )",
+ 1,
+ eval("var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r', 10 )") );
+
+new TestCase( SECTION,
+ "var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r' )",
+ 1,
+ eval("var b = true; b.__proto__.lastIndexOf = String.prototype.lastIndexOf; b.lastIndexOf('r' )") );
+
+test();
+
+function LastIndexOf( string, search, position ) {
+ string = String( string );
+ search = String( search );
+
+ position = Number( position )
+
+ if ( isNaN( position ) ) {
+ position = Infinity;
+ } else {
+ position = ToInteger( position );
+ }
+
+ result5= string.length;
+ result6 = Math.min(Math.max(position, 0), result5);
+ result7 = search.length;
+
+ if (result7 == 0) {
+ return Math.min(position, result5);
+ }
+
+ result8 = -1;
+
+ for ( k = 0; k <= result6; k++ ) {
+ if ( k+ result7 > result5 ) {
+ break;
+ }
+ for ( j = 0; j < result7; j++ ) {
+ if ( string.charAt(k+j) != search.charAt(j) ){
+ break;
+ } else {
+ if ( j == result7 -1 ) {
+ result8 = k;
+ }
+ }
+ }
+ }
+
+ return result8;
+}
+function ToInteger( n ) {
+ n = Number( n );
+ if ( isNaN(n) ) {
+ return 0;
+ }
+ if ( Math.abs(n) == 0 || Math.abs(n) == Infinity ) {
+ return n;
+ }
+
+ var sign = ( n < 0 ) ? -1 : 1;
+
+ return ( sign * Math.floor(Math.abs(n)) );
+}