summaryrefslogtreecommitdiffstats
path: root/gfx/cairo/libpixman/src/pixman-radial-gradient.c
diff options
context:
space:
mode:
authorMatt A. Tobin <mattatobin@localhost.localdomain>2018-02-02 04:16:08 -0500
committerMatt A. Tobin <mattatobin@localhost.localdomain>2018-02-02 04:16:08 -0500
commit5f8de423f190bbb79a62f804151bc24824fa32d8 (patch)
tree10027f336435511475e392454359edea8e25895d /gfx/cairo/libpixman/src/pixman-radial-gradient.c
parent49ee0794b5d912db1f95dce6eb52d781dc210db5 (diff)
downloadUXP-5f8de423f190bbb79a62f804151bc24824fa32d8.tar
UXP-5f8de423f190bbb79a62f804151bc24824fa32d8.tar.gz
UXP-5f8de423f190bbb79a62f804151bc24824fa32d8.tar.lz
UXP-5f8de423f190bbb79a62f804151bc24824fa32d8.tar.xz
UXP-5f8de423f190bbb79a62f804151bc24824fa32d8.zip
Add m-esr52 at 52.6.0
Diffstat (limited to 'gfx/cairo/libpixman/src/pixman-radial-gradient.c')
-rw-r--r--gfx/cairo/libpixman/src/pixman-radial-gradient.c727
1 files changed, 727 insertions, 0 deletions
diff --git a/gfx/cairo/libpixman/src/pixman-radial-gradient.c b/gfx/cairo/libpixman/src/pixman-radial-gradient.c
new file mode 100644
index 000000000..3d539b1c8
--- /dev/null
+++ b/gfx/cairo/libpixman/src/pixman-radial-gradient.c
@@ -0,0 +1,727 @@
+/* -*- Mode: c; c-basic-offset: 4; tab-width: 8; indent-tabs-mode: t; -*- */
+/*
+ *
+ * Copyright © 2000 Keith Packard, member of The XFree86 Project, Inc.
+ * Copyright © 2000 SuSE, Inc.
+ * 2005 Lars Knoll & Zack Rusin, Trolltech
+ * Copyright © 2007 Red Hat, Inc.
+ *
+ *
+ * Permission to use, copy, modify, distribute, and sell this software and its
+ * documentation for any purpose is hereby granted without fee, provided that
+ * the above copyright notice appear in all copies and that both that
+ * copyright notice and this permission notice appear in supporting
+ * documentation, and that the name of Keith Packard not be used in
+ * advertising or publicity pertaining to distribution of the software without
+ * specific, written prior permission. Keith Packard makes no
+ * representations about the suitability of this software for any purpose. It
+ * is provided "as is" without express or implied warranty.
+ *
+ * THE COPYRIGHT HOLDERS DISCLAIM ALL WARRANTIES WITH REGARD TO THIS
+ * SOFTWARE, INCLUDING ALL IMPLIED WARRANTIES OF MERCHANTABILITY AND
+ * FITNESS, IN NO EVENT SHALL THE COPYRIGHT HOLDERS BE LIABLE FOR ANY
+ * SPECIAL, INDIRECT OR CONSEQUENTIAL DAMAGES OR ANY DAMAGES
+ * WHATSOEVER RESULTING FROM LOSS OF USE, DATA OR PROFITS, WHETHER IN
+ * AN ACTION OF CONTRACT, NEGLIGENCE OR OTHER TORTIOUS ACTION, ARISING
+ * OUT OF OR IN CONNECTION WITH THE USE OR PERFORMANCE OF THIS
+ * SOFTWARE.
+ */
+
+#ifdef HAVE_CONFIG_H
+#include <config.h>
+#endif
+#include <stdlib.h>
+#include <math.h>
+#include "pixman-private.h"
+
+#include "pixman-dither.h"
+
+static inline pixman_fixed_32_32_t
+dot (pixman_fixed_48_16_t x1,
+ pixman_fixed_48_16_t y1,
+ pixman_fixed_48_16_t z1,
+ pixman_fixed_48_16_t x2,
+ pixman_fixed_48_16_t y2,
+ pixman_fixed_48_16_t z2)
+{
+ /*
+ * Exact computation, assuming that the input values can
+ * be represented as pixman_fixed_16_16_t
+ */
+ return x1 * x2 + y1 * y2 + z1 * z2;
+}
+
+static inline double
+fdot (double x1,
+ double y1,
+ double z1,
+ double x2,
+ double y2,
+ double z2)
+{
+ /*
+ * Error can be unbound in some special cases.
+ * Using clever dot product algorithms (for example compensated
+ * dot product) would improve this but make the code much less
+ * obvious
+ */
+ return x1 * x2 + y1 * y2 + z1 * z2;
+}
+
+static uint32_t
+radial_compute_color (double a,
+ double b,
+ double c,
+ double inva,
+ double dr,
+ double mindr,
+ pixman_gradient_walker_t *walker,
+ pixman_repeat_t repeat)
+{
+ /*
+ * In this function error propagation can lead to bad results:
+ * - discr can have an unbound error (if b*b-a*c is very small),
+ * potentially making it the opposite sign of what it should have been
+ * (thus clearing a pixel that would have been colored or vice-versa)
+ * or propagating the error to sqrtdiscr;
+ * if discr has the wrong sign or b is very small, this can lead to bad
+ * results
+ *
+ * - the algorithm used to compute the solutions of the quadratic
+ * equation is not numerically stable (but saves one division compared
+ * to the numerically stable one);
+ * this can be a problem if a*c is much smaller than b*b
+ *
+ * - the above problems are worse if a is small (as inva becomes bigger)
+ */
+ double discr;
+
+ if (a == 0)
+ {
+ double t;
+
+ if (b == 0)
+ return 0;
+
+ t = pixman_fixed_1 / 2 * c / b;
+ if (repeat == PIXMAN_REPEAT_NONE)
+ {
+ if (0 <= t && t <= pixman_fixed_1)
+ return _pixman_gradient_walker_pixel (walker, t);
+ }
+ else
+ {
+ if (t * dr >= mindr)
+ return _pixman_gradient_walker_pixel (walker, t);
+ }
+
+ return 0;
+ }
+
+ discr = fdot (b, a, 0, b, -c, 0);
+ if (discr >= 0)
+ {
+ double sqrtdiscr, t0, t1;
+
+ sqrtdiscr = sqrt (discr);
+ t0 = (b + sqrtdiscr) * inva;
+ t1 = (b - sqrtdiscr) * inva;
+
+ /*
+ * The root that must be used is the biggest one that belongs
+ * to the valid range ([0,1] for PIXMAN_REPEAT_NONE, any
+ * solution that results in a positive radius otherwise).
+ *
+ * If a > 0, t0 is the biggest solution, so if it is valid, it
+ * is the correct result.
+ *
+ * If a < 0, only one of the solutions can be valid, so the
+ * order in which they are tested is not important.
+ */
+ if (repeat == PIXMAN_REPEAT_NONE)
+ {
+ if (0 <= t0 && t0 <= pixman_fixed_1)
+ return _pixman_gradient_walker_pixel (walker, t0);
+ else if (0 <= t1 && t1 <= pixman_fixed_1)
+ return _pixman_gradient_walker_pixel (walker, t1);
+ }
+ else
+ {
+ if (t0 * dr >= mindr)
+ return _pixman_gradient_walker_pixel (walker, t0);
+ else if (t1 * dr >= mindr)
+ return _pixman_gradient_walker_pixel (walker, t1);
+ }
+ }
+
+ return 0;
+}
+
+static uint32_t *
+radial_get_scanline_narrow (pixman_iter_t *iter, const uint32_t *mask)
+{
+ /*
+ * Implementation of radial gradients following the PDF specification.
+ * See section 8.7.4.5.4 Type 3 (Radial) Shadings of the PDF Reference
+ * Manual (PDF 32000-1:2008 at the time of this writing).
+ *
+ * In the radial gradient problem we are given two circles (c₁,r₁) and
+ * (c₂,r₂) that define the gradient itself.
+ *
+ * Mathematically the gradient can be defined as the family of circles
+ *
+ * ((1-t)·c₁ + t·(c₂), (1-t)·r₁ + t·r₂)
+ *
+ * excluding those circles whose radius would be < 0. When a point
+ * belongs to more than one circle, the one with a bigger t is the only
+ * one that contributes to its color. When a point does not belong
+ * to any of the circles, it is transparent black, i.e. RGBA (0, 0, 0, 0).
+ * Further limitations on the range of values for t are imposed when
+ * the gradient is not repeated, namely t must belong to [0,1].
+ *
+ * The graphical result is the same as drawing the valid (radius > 0)
+ * circles with increasing t in [-inf, +inf] (or in [0,1] if the gradient
+ * is not repeated) using SOURCE operator composition.
+ *
+ * It looks like a cone pointing towards the viewer if the ending circle
+ * is smaller than the starting one, a cone pointing inside the page if
+ * the starting circle is the smaller one and like a cylinder if they
+ * have the same radius.
+ *
+ * What we actually do is, given the point whose color we are interested
+ * in, compute the t values for that point, solving for t in:
+ *
+ * length((1-t)·c₁ + t·(c₂) - p) = (1-t)·r₁ + t·r₂
+ *
+ * Let's rewrite it in a simpler way, by defining some auxiliary
+ * variables:
+ *
+ * cd = c₂ - c₁
+ * pd = p - c₁
+ * dr = r₂ - r₁
+ * length(t·cd - pd) = r₁ + t·dr
+ *
+ * which actually means
+ *
+ * hypot(t·cdx - pdx, t·cdy - pdy) = r₁ + t·dr
+ *
+ * or
+ *
+ * ⎷((t·cdx - pdx)² + (t·cdy - pdy)²) = r₁ + t·dr.
+ *
+ * If we impose (as stated earlier) that r₁ + t·dr >= 0, it becomes:
+ *
+ * (t·cdx - pdx)² + (t·cdy - pdy)² = (r₁ + t·dr)²
+ *
+ * where we can actually expand the squares and solve for t:
+ *
+ * t²cdx² - 2t·cdx·pdx + pdx² + t²cdy² - 2t·cdy·pdy + pdy² =
+ * = r₁² + 2·r₁·t·dr + t²·dr²
+ *
+ * (cdx² + cdy² - dr²)t² - 2(cdx·pdx + cdy·pdy + r₁·dr)t +
+ * (pdx² + pdy² - r₁²) = 0
+ *
+ * A = cdx² + cdy² - dr²
+ * B = pdx·cdx + pdy·cdy + r₁·dr
+ * C = pdx² + pdy² - r₁²
+ * At² - 2Bt + C = 0
+ *
+ * The solutions (unless the equation degenerates because of A = 0) are:
+ *
+ * t = (B ± ⎷(B² - A·C)) / A
+ *
+ * The solution we are going to prefer is the bigger one, unless the
+ * radius associated to it is negative (or it falls outside the valid t
+ * range).
+ *
+ * Additional observations (useful for optimizations):
+ * A does not depend on p
+ *
+ * A < 0 <=> one of the two circles completely contains the other one
+ * <=> for every p, the radiuses associated with the two t solutions
+ * have opposite sign
+ */
+ pixman_image_t *image = iter->image;
+ int x = iter->x;
+ int y = iter->y;
+ int width = iter->width;
+ uint32_t *buffer = iter->buffer;
+
+ gradient_t *gradient = (gradient_t *)image;
+ radial_gradient_t *radial = (radial_gradient_t *)image;
+ uint32_t *end = buffer + width;
+ pixman_gradient_walker_t walker;
+ pixman_vector_t v, unit;
+
+ /* reference point is the center of the pixel */
+ v.vector[0] = pixman_int_to_fixed (x) + pixman_fixed_1 / 2;
+ v.vector[1] = pixman_int_to_fixed (y) + pixman_fixed_1 / 2;
+ v.vector[2] = pixman_fixed_1;
+
+ _pixman_gradient_walker_init (&walker, gradient, image->common.repeat);
+
+ if (image->common.transform)
+ {
+ if (!pixman_transform_point_3d (image->common.transform, &v))
+ return iter->buffer;
+
+ unit.vector[0] = image->common.transform->matrix[0][0];
+ unit.vector[1] = image->common.transform->matrix[1][0];
+ unit.vector[2] = image->common.transform->matrix[2][0];
+ }
+ else
+ {
+ unit.vector[0] = pixman_fixed_1;
+ unit.vector[1] = 0;
+ unit.vector[2] = 0;
+ }
+
+ if (unit.vector[2] == 0 && v.vector[2] == pixman_fixed_1)
+ {
+ /*
+ * Given:
+ *
+ * t = (B ± ⎷(B² - A·C)) / A
+ *
+ * where
+ *
+ * A = cdx² + cdy² - dr²
+ * B = pdx·cdx + pdy·cdy + r₁·dr
+ * C = pdx² + pdy² - r₁²
+ * det = B² - A·C
+ *
+ * Since we have an affine transformation, we know that (pdx, pdy)
+ * increase linearly with each pixel,
+ *
+ * pdx = pdx₀ + n·ux,
+ * pdy = pdy₀ + n·uy,
+ *
+ * we can then express B, C and det through multiple differentiation.
+ */
+ pixman_fixed_32_32_t b, db, c, dc, ddc;
+
+ /* warning: this computation may overflow */
+ v.vector[0] -= radial->c1.x;
+ v.vector[1] -= radial->c1.y;
+
+ /*
+ * B and C are computed and updated exactly.
+ * If fdot was used instead of dot, in the worst case it would
+ * lose 11 bits of precision in each of the multiplication and
+ * summing up would zero out all the bit that were preserved,
+ * thus making the result 0 instead of the correct one.
+ * This would mean a worst case of unbound relative error or
+ * about 2^10 absolute error
+ */
+ b = dot (v.vector[0], v.vector[1], radial->c1.radius,
+ radial->delta.x, radial->delta.y, radial->delta.radius);
+ db = dot (unit.vector[0], unit.vector[1], 0,
+ radial->delta.x, radial->delta.y, 0);
+
+ c = dot (v.vector[0], v.vector[1],
+ -((pixman_fixed_48_16_t) radial->c1.radius),
+ v.vector[0], v.vector[1], radial->c1.radius);
+ dc = dot (2 * (pixman_fixed_48_16_t) v.vector[0] + unit.vector[0],
+ 2 * (pixman_fixed_48_16_t) v.vector[1] + unit.vector[1],
+ 0,
+ unit.vector[0], unit.vector[1], 0);
+ ddc = 2 * dot (unit.vector[0], unit.vector[1], 0,
+ unit.vector[0], unit.vector[1], 0);
+
+ while (buffer < end)
+ {
+ if (!mask || *mask++)
+ {
+ *buffer = radial_compute_color (radial->a, b, c,
+ radial->inva,
+ radial->delta.radius,
+ radial->mindr,
+ &walker,
+ image->common.repeat);
+ }
+
+ b += db;
+ c += dc;
+ dc += ddc;
+ ++buffer;
+ }
+ }
+ else
+ {
+ /* projective */
+ /* Warning:
+ * error propagation guarantees are much looser than in the affine case
+ */
+ while (buffer < end)
+ {
+ if (!mask || *mask++)
+ {
+ if (v.vector[2] != 0)
+ {
+ double pdx, pdy, invv2, b, c;
+
+ invv2 = 1. * pixman_fixed_1 / v.vector[2];
+
+ pdx = v.vector[0] * invv2 - radial->c1.x;
+ /* / pixman_fixed_1 */
+
+ pdy = v.vector[1] * invv2 - radial->c1.y;
+ /* / pixman_fixed_1 */
+
+ b = fdot (pdx, pdy, radial->c1.radius,
+ radial->delta.x, radial->delta.y,
+ radial->delta.radius);
+ /* / pixman_fixed_1 / pixman_fixed_1 */
+
+ c = fdot (pdx, pdy, -radial->c1.radius,
+ pdx, pdy, radial->c1.radius);
+ /* / pixman_fixed_1 / pixman_fixed_1 */
+
+ *buffer = radial_compute_color (radial->a, b, c,
+ radial->inva,
+ radial->delta.radius,
+ radial->mindr,
+ &walker,
+ image->common.repeat);
+ }
+ else
+ {
+ *buffer = 0;
+ }
+ }
+
+ ++buffer;
+
+ v.vector[0] += unit.vector[0];
+ v.vector[1] += unit.vector[1];
+ v.vector[2] += unit.vector[2];
+ }
+ }
+
+ iter->y++;
+ return iter->buffer;
+}
+
+static uint32_t *
+radial_get_scanline_16 (pixman_iter_t *iter, const uint32_t *mask)
+{
+ /*
+ * Implementation of radial gradients following the PDF specification.
+ * See section 8.7.4.5.4 Type 3 (Radial) Shadings of the PDF Reference
+ * Manual (PDF 32000-1:2008 at the time of this writing).
+ *
+ * In the radial gradient problem we are given two circles (c₁,r₁) and
+ * (c₂,r₂) that define the gradient itself.
+ *
+ * Mathematically the gradient can be defined as the family of circles
+ *
+ * ((1-t)·c₁ + t·(c₂), (1-t)·r₁ + t·r₂)
+ *
+ * excluding those circles whose radius would be < 0. When a point
+ * belongs to more than one circle, the one with a bigger t is the only
+ * one that contributes to its color. When a point does not belong
+ * to any of the circles, it is transparent black, i.e. RGBA (0, 0, 0, 0).
+ * Further limitations on the range of values for t are imposed when
+ * the gradient is not repeated, namely t must belong to [0,1].
+ *
+ * The graphical result is the same as drawing the valid (radius > 0)
+ * circles with increasing t in [-inf, +inf] (or in [0,1] if the gradient
+ * is not repeated) using SOURCE operator composition.
+ *
+ * It looks like a cone pointing towards the viewer if the ending circle
+ * is smaller than the starting one, a cone pointing inside the page if
+ * the starting circle is the smaller one and like a cylinder if they
+ * have the same radius.
+ *
+ * What we actually do is, given the point whose color we are interested
+ * in, compute the t values for that point, solving for t in:
+ *
+ * length((1-t)·c₁ + t·(c₂) - p) = (1-t)·r₁ + t·r₂
+ *
+ * Let's rewrite it in a simpler way, by defining some auxiliary
+ * variables:
+ *
+ * cd = c₂ - c₁
+ * pd = p - c₁
+ * dr = r₂ - r₁
+ * length(t·cd - pd) = r₁ + t·dr
+ *
+ * which actually means
+ *
+ * hypot(t·cdx - pdx, t·cdy - pdy) = r₁ + t·dr
+ *
+ * or
+ *
+ * ⎷((t·cdx - pdx)² + (t·cdy - pdy)²) = r₁ + t·dr.
+ *
+ * If we impose (as stated earlier) that r₁ + t·dr >= 0, it becomes:
+ *
+ * (t·cdx - pdx)² + (t·cdy - pdy)² = (r₁ + t·dr)²
+ *
+ * where we can actually expand the squares and solve for t:
+ *
+ * t²cdx² - 2t·cdx·pdx + pdx² + t²cdy² - 2t·cdy·pdy + pdy² =
+ * = r₁² + 2·r₁·t·dr + t²·dr²
+ *
+ * (cdx² + cdy² - dr²)t² - 2(cdx·pdx + cdy·pdy + r₁·dr)t +
+ * (pdx² + pdy² - r₁²) = 0
+ *
+ * A = cdx² + cdy² - dr²
+ * B = pdx·cdx + pdy·cdy + r₁·dr
+ * C = pdx² + pdy² - r₁²
+ * At² - 2Bt + C = 0
+ *
+ * The solutions (unless the equation degenerates because of A = 0) are:
+ *
+ * t = (B ± ⎷(B² - A·C)) / A
+ *
+ * The solution we are going to prefer is the bigger one, unless the
+ * radius associated to it is negative (or it falls outside the valid t
+ * range).
+ *
+ * Additional observations (useful for optimizations):
+ * A does not depend on p
+ *
+ * A < 0 <=> one of the two circles completely contains the other one
+ * <=> for every p, the radiuses associated with the two t solutions
+ * have opposite sign
+ */
+ pixman_image_t *image = iter->image;
+ int x = iter->x;
+ int y = iter->y;
+ int width = iter->width;
+ uint16_t *buffer = iter->buffer;
+ pixman_bool_t toggle = ((x ^ y) & 1);
+
+ gradient_t *gradient = (gradient_t *)image;
+ radial_gradient_t *radial = (radial_gradient_t *)image;
+ uint16_t *end = buffer + width;
+ pixman_gradient_walker_t walker;
+ pixman_vector_t v, unit;
+
+ /* reference point is the center of the pixel */
+ v.vector[0] = pixman_int_to_fixed (x) + pixman_fixed_1 / 2;
+ v.vector[1] = pixman_int_to_fixed (y) + pixman_fixed_1 / 2;
+ v.vector[2] = pixman_fixed_1;
+
+ _pixman_gradient_walker_init (&walker, gradient, image->common.repeat);
+
+ if (image->common.transform)
+ {
+ if (!pixman_transform_point_3d (image->common.transform, &v))
+ return iter->buffer;
+
+ unit.vector[0] = image->common.transform->matrix[0][0];
+ unit.vector[1] = image->common.transform->matrix[1][0];
+ unit.vector[2] = image->common.transform->matrix[2][0];
+ }
+ else
+ {
+ unit.vector[0] = pixman_fixed_1;
+ unit.vector[1] = 0;
+ unit.vector[2] = 0;
+ }
+
+ if (unit.vector[2] == 0 && v.vector[2] == pixman_fixed_1)
+ {
+ /*
+ * Given:
+ *
+ * t = (B ± ⎷(B² - A·C)) / A
+ *
+ * where
+ *
+ * A = cdx² + cdy² - dr²
+ * B = pdx·cdx + pdy·cdy + r₁·dr
+ * C = pdx² + pdy² - r₁²
+ * det = B² - A·C
+ *
+ * Since we have an affine transformation, we know that (pdx, pdy)
+ * increase linearly with each pixel,
+ *
+ * pdx = pdx₀ + n·ux,
+ * pdy = pdy₀ + n·uy,
+ *
+ * we can then express B, C and det through multiple differentiation.
+ */
+ pixman_fixed_32_32_t b, db, c, dc, ddc;
+
+ /* warning: this computation may overflow */
+ v.vector[0] -= radial->c1.x;
+ v.vector[1] -= radial->c1.y;
+
+ /*
+ * B and C are computed and updated exactly.
+ * If fdot was used instead of dot, in the worst case it would
+ * lose 11 bits of precision in each of the multiplication and
+ * summing up would zero out all the bit that were preserved,
+ * thus making the result 0 instead of the correct one.
+ * This would mean a worst case of unbound relative error or
+ * about 2^10 absolute error
+ */
+ b = dot (v.vector[0], v.vector[1], radial->c1.radius,
+ radial->delta.x, radial->delta.y, radial->delta.radius);
+ db = dot (unit.vector[0], unit.vector[1], 0,
+ radial->delta.x, radial->delta.y, 0);
+
+ c = dot (v.vector[0], v.vector[1],
+ -((pixman_fixed_48_16_t) radial->c1.radius),
+ v.vector[0], v.vector[1], radial->c1.radius);
+ dc = dot (2 * (pixman_fixed_48_16_t) v.vector[0] + unit.vector[0],
+ 2 * (pixman_fixed_48_16_t) v.vector[1] + unit.vector[1],
+ 0,
+ unit.vector[0], unit.vector[1], 0);
+ ddc = 2 * dot (unit.vector[0], unit.vector[1], 0,
+ unit.vector[0], unit.vector[1], 0);
+
+ while (buffer < end)
+ {
+ if (!mask || *mask++)
+ {
+ *buffer = dither_8888_to_0565(
+ radial_compute_color (radial->a, b, c,
+ radial->inva,
+ radial->delta.radius,
+ radial->mindr,
+ &walker,
+ image->common.repeat),
+ toggle);
+ }
+
+ toggle ^= 1;
+ b += db;
+ c += dc;
+ dc += ddc;
+ ++buffer;
+ }
+ }
+ else
+ {
+ /* projective */
+ /* Warning:
+ * error propagation guarantees are much looser than in the affine case
+ */
+ while (buffer < end)
+ {
+ if (!mask || *mask++)
+ {
+ if (v.vector[2] != 0)
+ {
+ double pdx, pdy, invv2, b, c;
+
+ invv2 = 1. * pixman_fixed_1 / v.vector[2];
+
+ pdx = v.vector[0] * invv2 - radial->c1.x;
+ /* / pixman_fixed_1 */
+
+ pdy = v.vector[1] * invv2 - radial->c1.y;
+ /* / pixman_fixed_1 */
+
+ b = fdot (pdx, pdy, radial->c1.radius,
+ radial->delta.x, radial->delta.y,
+ radial->delta.radius);
+ /* / pixman_fixed_1 / pixman_fixed_1 */
+
+ c = fdot (pdx, pdy, -radial->c1.radius,
+ pdx, pdy, radial->c1.radius);
+ /* / pixman_fixed_1 / pixman_fixed_1 */
+
+ *buffer = dither_8888_to_0565 (
+ radial_compute_color (radial->a, b, c,
+ radial->inva,
+ radial->delta.radius,
+ radial->mindr,
+ &walker,
+ image->common.repeat),
+ toggle);
+ }
+ else
+ {
+ *buffer = 0;
+ }
+ }
+
+ ++buffer;
+ toggle ^= 1;
+
+ v.vector[0] += unit.vector[0];
+ v.vector[1] += unit.vector[1];
+ v.vector[2] += unit.vector[2];
+ }
+ }
+
+ iter->y++;
+ return iter->buffer;
+}
+static uint32_t *
+radial_get_scanline_wide (pixman_iter_t *iter, const uint32_t *mask)
+{
+ uint32_t *buffer = radial_get_scanline_narrow (iter, NULL);
+
+ pixman_expand_to_float (
+ (argb_t *)buffer, buffer, PIXMAN_a8r8g8b8, iter->width);
+
+ return buffer;
+}
+
+void
+_pixman_radial_gradient_iter_init (pixman_image_t *image, pixman_iter_t *iter)
+{
+ if (iter->iter_flags & ITER_16)
+ iter->get_scanline = radial_get_scanline_16;
+ else if (iter->iter_flags & ITER_NARROW)
+ iter->get_scanline = radial_get_scanline_narrow;
+ else
+ iter->get_scanline = radial_get_scanline_wide;
+}
+
+
+PIXMAN_EXPORT pixman_image_t *
+pixman_image_create_radial_gradient (const pixman_point_fixed_t * inner,
+ const pixman_point_fixed_t * outer,
+ pixman_fixed_t inner_radius,
+ pixman_fixed_t outer_radius,
+ const pixman_gradient_stop_t *stops,
+ int n_stops)
+{
+ pixman_image_t *image;
+ radial_gradient_t *radial;
+
+ image = _pixman_image_allocate ();
+
+ if (!image)
+ return NULL;
+
+ radial = &image->radial;
+
+ if (!_pixman_init_gradient (&radial->common, stops, n_stops))
+ {
+ free (image);
+ return NULL;
+ }
+
+ image->type = RADIAL;
+
+ radial->c1.x = inner->x;
+ radial->c1.y = inner->y;
+ radial->c1.radius = inner_radius;
+ radial->c2.x = outer->x;
+ radial->c2.y = outer->y;
+ radial->c2.radius = outer_radius;
+
+ /* warning: this computations may overflow */
+ radial->delta.x = radial->c2.x - radial->c1.x;
+ radial->delta.y = radial->c2.y - radial->c1.y;
+ radial->delta.radius = radial->c2.radius - radial->c1.radius;
+
+ /* computed exactly, then cast to double -> every bit of the double
+ representation is correct (53 bits) */
+ radial->a = dot (radial->delta.x, radial->delta.y, -radial->delta.radius,
+ radial->delta.x, radial->delta.y, radial->delta.radius);
+ if (radial->a != 0)
+ radial->inva = 1. * pixman_fixed_1 / radial->a;
+
+ radial->mindr = -1. * pixman_fixed_1 * radial->c1.radius;
+
+ return image;
+}