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authorMatt A. Tobin <mattatobin@localhost.localdomain>2018-02-02 04:16:08 -0500
committerMatt A. Tobin <mattatobin@localhost.localdomain>2018-02-02 04:16:08 -0500
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+/* -*- indent-tabs-mode: nil; js-indent-level: 2 -*- */
+/* This Source Code Form is subject to the terms of the Mozilla Public
+ * License, v. 2.0. If a copy of the MPL was not distributed with this
+ * file, You can obtain one at http://mozilla.org/MPL/2.0/. */
+
+
+/**
+ File Name: 11.5.2.js
+ ECMA Section: 11.5.2 Applying the / operator
+ Description:
+
+ The / operator performs division, producing the quotient of its operands.
+ The left operand is the dividend and the right operand is the divisor.
+ ECMAScript does not perform integer division. The operands and result of all
+ division operations are double-precision floating-point numbers.
+ The result of division is determined by the specification of IEEE 754 arithmetic:
+
+ If either operand is NaN, the result is NaN.
+ The sign of the result is positive if both operands have the same sign, negative if the operands have different
+ signs.
+ Division of an infinity by an infinity results in NaN.
+ Division of an infinity by a zero results in an infinity. The sign is determined by the rule already stated above.
+ Division of an infinity by a non-zero finite value results in a signed infinity. The sign is determined by the rule
+ already stated above.
+ Division of a finite value by an infinity results in zero. The sign is determined by the rule already stated above.
+ Division of a zero by a zero results in NaN; division of zero by any other finite value results in zero, with the sign
+ determined by the rule already stated above.
+ Division of a non-zero finite value by a zero results in a signed infinity. The sign is determined by the rule
+ already stated above.
+ In the remaining cases, where neither an infinity, nor a zero, nor NaN is involved, the quotient is computed and
+ rounded to the nearest representable value using IEEE 754 round-to-nearest mode. If the magnitude is too
+ large to represent, we say the operation overflows; the result is then an infinity of appropriate sign. If the
+ magnitude is too small to represent, we say the operation underflows and the result is a zero of the appropriate
+ sign. The ECMAScript language requires support of gradual underflow as defined by IEEE 754.
+
+ Author: christine@netscape.com
+ Date: 12 november 1997
+*/
+var SECTION = "11.5.2";
+var VERSION = "ECMA_1";
+var BUGNUMBER="111202";
+startTest();
+
+writeHeaderToLog( SECTION + " Applying the / operator");
+
+// if either operand is NaN, the result is NaN.
+
+new TestCase( SECTION, "Number.NaN / Number.NaN", Number.NaN, Number.NaN / Number.NaN );
+new TestCase( SECTION, "Number.NaN / 1", Number.NaN, Number.NaN / 1 );
+new TestCase( SECTION, "1 / Number.NaN", Number.NaN, 1 / Number.NaN );
+
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.NaN", Number.NaN, Number.POSITIVE_INFINITY / Number.NaN );
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.NaN", Number.NaN, Number.NEGATIVE_INFINITY / Number.NaN );
+
+// Division of an infinity by an infinity results in NaN.
+
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY / Number.NEGATIVE_INFINITY );
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY / Number.NEGATIVE_INFINITY );
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY", Number.NaN, Number.NEGATIVE_INFINITY / Number.POSITIVE_INFINITY );
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY", Number.NaN, Number.POSITIVE_INFINITY / Number.POSITIVE_INFINITY );
+
+// Division of an infinity by a zero results in an infinity.
+
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / 0", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / 0 );
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / 0", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / 0 );
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / -0", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -0 );
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -0", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -0 );
+
+// Division of an infinity by a non-zero finite value results in a signed infinity.
+
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / 1 ", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / 1 );
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -1 ", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -1 );
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / 1 ", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / 1 );
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / -1 ", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -1 );
+
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / Number.MAX_VALUE ", Number.NEGATIVE_INFINITY, Number.NEGATIVE_INFINITY / Number.MAX_VALUE );
+new TestCase( SECTION, "Number.NEGATIVE_INFINITY / -Number.MAX_VALUE ", Number.POSITIVE_INFINITY, Number.NEGATIVE_INFINITY / -Number.MAX_VALUE );
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / Number.MAX_VALUE ", Number.POSITIVE_INFINITY, Number.POSITIVE_INFINITY / Number.MAX_VALUE );
+new TestCase( SECTION, "Number.POSITIVE_INFINITY / -Number.MAX_VALUE ", Number.NEGATIVE_INFINITY, Number.POSITIVE_INFINITY / -Number.MAX_VALUE );
+
+// Division of a finite value by an infinity results in zero.
+
+new TestCase( SECTION, "1 / Number.NEGATIVE_INFINITY", -0, 1 / Number.NEGATIVE_INFINITY );
+new TestCase( SECTION, "1 / Number.POSITIVE_INFINITY", 0, 1 / Number.POSITIVE_INFINITY );
+new TestCase( SECTION, "-1 / Number.POSITIVE_INFINITY", -0, -1 / Number.POSITIVE_INFINITY );
+new TestCase( SECTION, "-1 / Number.NEGATIVE_INFINITY", 0, -1 / Number.NEGATIVE_INFINITY );
+
+new TestCase( SECTION, "Number.MAX_VALUE / Number.NEGATIVE_INFINITY", -0, Number.MAX_VALUE / Number.NEGATIVE_INFINITY );
+new TestCase( SECTION, "Number.MAX_VALUE / Number.POSITIVE_INFINITY", 0, Number.MAX_VALUE / Number.POSITIVE_INFINITY );
+new TestCase( SECTION, "-Number.MAX_VALUE / Number.POSITIVE_INFINITY", -0, -Number.MAX_VALUE / Number.POSITIVE_INFINITY );
+new TestCase( SECTION, "-Number.MAX_VALUE / Number.NEGATIVE_INFINITY", 0, -Number.MAX_VALUE / Number.NEGATIVE_INFINITY );
+
+// Division of a zero by a zero results in NaN
+
+new TestCase( SECTION, "0 / -0", Number.NaN, 0 / -0 );
+new TestCase( SECTION, "-0 / 0", Number.NaN, -0 / 0 );
+new TestCase( SECTION, "-0 / -0", Number.NaN, -0 / -0 );
+new TestCase( SECTION, "0 / 0", Number.NaN, 0 / 0 );
+
+// division of zero by any other finite value results in zero
+
+new TestCase( SECTION, "0 / 1", 0, 0 / 1 );
+new TestCase( SECTION, "0 / -1", -0, 0 / -1 );
+new TestCase( SECTION, "-0 / 1", -0, -0 / 1 );
+new TestCase( SECTION, "-0 / -1", 0, -0 / -1 );
+
+// Division of a non-zero finite value by a zero results in a signed infinity.
+
+new TestCase( SECTION, "1 / 0", Number.POSITIVE_INFINITY, 1/0 );
+new TestCase( SECTION, "1 / -0", Number.NEGATIVE_INFINITY, 1/-0 );
+new TestCase( SECTION, "-1 / 0", Number.NEGATIVE_INFINITY, -1/0 );
+new TestCase( SECTION, "-1 / -0", Number.POSITIVE_INFINITY, -1/-0 );
+
+new TestCase( SECTION, "0 / Number.POSITIVE_INFINITY", 0, 0 / Number.POSITIVE_INFINITY );
+new TestCase( SECTION, "0 / Number.NEGATIVE_INFINITY", -0, 0 / Number.NEGATIVE_INFINITY );
+new TestCase( SECTION, "-0 / Number.POSITIVE_INFINITY", -0, -0 / Number.POSITIVE_INFINITY );
+new TestCase( SECTION, "-0 / Number.NEGATIVE_INFINITY", 0, -0 / Number.NEGATIVE_INFINITY );
+
+test();
+