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authorMatt A. Tobin <mattatobin@localhost.localdomain>2018-02-02 04:16:08 -0500
committerMatt A. Tobin <mattatobin@localhost.localdomain>2018-02-02 04:16:08 -0500
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Add m-esr52 at 52.6.0
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+// Bug 1099956
+
+load(libdir + "asserts.js");
+
+// ES6 treating yield as an identifier except in ES6 generators introduces a
+// syntax conflict with permissible JS >= 1.7 legacy generator syntax. Is
+// |yield /a/g| inside a function an attempt to convert the function into a
+// legacy generator, yielding a RegExp instance? Or does it instead read as
+// |(yield / a) / g|? Similar ambiguities exist for different textual content
+// in place of |a| -- |yield /x+17/g| or |(yield / x) + 17 / g|, and so on.
+// (And, much less importantly, is |yield /a/g| a syntax error in global code
+// as in JS >= 1.7, or is it |(yield / a) / g|.)
+//
+// For now, in JS >= 1.7, we preserve the old behavior. In all other JS we
+// conform to ES6: |yield /a/g| is a YieldExpression inside an ES6 generator,
+// and it's an IdentifierReference divided twice when not in an ES6 generator.
+// This test will need changes if we change our JS >= 1.7 parsing to be
+// ES6-compatible.
+
+function f1() {
+ yield /abc/g;
+}
+
+var g = f1();
+var v;
+v = g.next();
+assertEq(v instanceof RegExp, true);
+assertEq(v.toString(), "/abc/g");
+assertThrowsValue(() => g.next(), StopIteration);
+
+function* f2() {
+ yield /abc/g;
+}
+
+g = f2();
+v = g.next();
+assertEq(v.done, false);
+assertEq(v.value instanceof RegExp, true);
+assertEq(v.value.toString(), "/abc/g");
+v = g.next();
+assertEq(v.done, true);